Question

Question 8 pls ........ I want exact answer....thx for the help

Answer 1

Answer:

(b) cannot be negative

Answer 2

Actually, to answer it, will can prove it as

D = $b^{2} - 4ac$

= $k^{2} - 4k$

= $k(k - 4)$

so, now in equation

x = $\frac{-k \sqrt{k(k - 4)}{2}$

now, in any case

- k will surely, be less than 0

also, it will greater than $\sqrt{D}$

hence, in any case

$<b>Roots are always negative</b>$

or you can do it through hit and trail method, as you can put any value the answer will be negative!!

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Hope You Get Your Answer Mate !!

#OoeAshu