Math, asked by dwivedi78, 8 months ago

Question 8
There are 7 boys and 8 girls and need to form a team of 5 boys and 6 girls. In how many ways can the team be formed?
432
481
ОО
588
232

Answers

Answered by pulakmath007
16

SOLUTION

GIVEN

There are 7 boys and 8 girls and need to form a team of 5 boys and 6 girls

TO CHOOSE THE CORRECT OPTION

The number of ways the team can be formed

  • 432

  • 481

  • 588

  • 232

EVALUATION

Here it is given that

Total number of boys = 7

Total number of girls = 8

Now we have to form a team of 5 boys and 6 girls

So the number of ways in which 5 boys can be selected from 7 boys

 \sf{ =  {}^{7}C_{5}  \: }

 \displaystyle \sf{  =  \frac{7! }{5! \:   2! } \: }

 \displaystyle \sf{  =  \frac{7 \times 6 }{2} \: }

 \displaystyle \sf{  = 21}

Again the number of ways in which 6 girls can be selected from 8 girls

 \sf{ =  {}^{8}C_{6}  \: }

 \displaystyle \sf{  =  \frac{8! }{6! \:   2! } \: }

 \displaystyle \sf{  =  \frac{8 \times 7}{2} \: }

 \displaystyle \sf{  =  28}

Hence the number of ways the team can be formed

 \sf{  = 21 \times 28\: }

 \sf{  = 588\: }

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