Question 9: 9.
16-a, x, 6+a are in AP, then the value of x is
6
0-6
12
0-12
Answers
Answered by
0
Answer:
??
I can't understand the meaning of this question
Answered by
0
Answer:
16-a,x,6+a are in AP
=>x-(16-a)=6+a-x
=>x-16+a=6+a-x
=>x+a-a+x=6+16
=>2x=22
=>x=22/2
=>x=11
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