Math, asked by Nandanshinganalli, 9 months ago

Question 9: 9.
16-a, x, 6+a are in AP, then the value of x is
6
0-6
12
0-12 ​

Answers

Answered by mdsaifreza950
0

Answer:

??

I can't understand the meaning of this question

Answered by Bidikha
0

Answer:

16-a,x,6+a are in AP

=>x-(16-a)=6+a-x

=>x-16+a=6+a-x

=>x+a-a+x=6+16

=>2x=22

=>x=22/2

=>x=11

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