Question 9
A jewel box ( see fig.) is in the shape of a cuboid of dimensions 30 cm x 15 cm x 10 cm
surmounted by a half part of a cylinder as shown in the figure. Then the volume of the box is
10 cm
15cm
30cm
a
O 7155.79 cm
07153.79 cm3
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Answers
Given : A jewel box ( see fig.) is in the shape of a cuboid of dimensions 30 cm x 15 cm x10 cm surmounted by a half part of a cylinder
To Find : volume of the box
Solution:
Volume of the box = Volume of the cuboid + Volume of half cylinder
Volume of cuboid = Length * Breadth * Height
=> Volume of cuboid = 30 x 15 x 10 = 4500 cm²
Volume of half cylinder = (1/2)πR²h
R = Radius = Diameter/2 = 15/2
h = Height = 30 cm
Volume of half cylinder = (1/2)π(15/2)²*30
= 3,375π/4
use π = 22/7
= 2,651.79 cm²
Volume of the box = 4500 + 2,651.79
= 7151.79 cm²
volume of the box is 7151.79 cm²
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HELLO DEAR,
ANSWER:-
GIVEN-A jewel box ( see fig.) is in the shape of a cuboid of dimensions 30 cm x 15 cm x 10 cm
surmounted by a half part of a cylinder as shown in the figure. Then the volume of the box is?
SOLUTION:- cuboid dimension
( 30×15×10).
Lenght = 30cm
Breath = 15cm
Height = 10cm
Volume of cuboid = (L×B×H)cm³
= (30×15×10)cm³
= 4500 cm³
And volume of box =( volume of cuboid + volume of half cylinder) = (4500 cm³+ volume of half cylinder)
So, volume of half cylinder= 1/2πr²h
where r = dimeter /2 ( dimeter = breath)
r = 15/2 = 7.5 cm
And height = lenght of cuboid
h = 30 cm.
Volume of half cylinder = 1/2πr²h
= 0.5× 3.14× 7.5×7.5 × 30
= 2649.3 cm³
Therefore volume of box =( 4500 + 2649.3) cm³
= 7149.3 cm³
I HOPE IT'S HELP YOU DEAR,
THANKS.
