Question

Question 9
The force acting on a charge of 20 placed in a field of
intensity 2 N/CIS?
(a) IN
(b) 4N
(c) 6N
(d) 8 N​

Answer 1

Answer:

E=5×104N/C

qE=−1.6×10−19C

F=EqE=5×104×−1.6×10−19=−8×10−15N