Question

Question :-
A ball is thrown upwards with a velocity of 10m/s. Find the maximum height reached by the ball and the time taken to come back to the thrower. (G = 10m /s ^2)
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Answer 1

QUESTION:

A ball is thrown upwards with a velocity of 10m s.Find the maximum height reached by the ball and the time taken to come back to the thrower(gravity 10m/s-2)

Explanation:

given that,

A ball is thrown upwards with a velocity of 10m s.

so , here

initial velocity of ball = 10 m/s

since ,

it threw in the upward direction

let the maximum height at which ball will reach be h

so, let at the maximum height final velocity be v,

so,

we have ,

initial velocity (u) = 10 m/s

final velocity (v) = 0

gravitational acceleration (g) = 10 m/s²

1.( by the motion formulae of gravitation

v² = u² + 2gh

now putting the values

(0)² = (10)² + 2(10)h

20h + 10000 = 0

20h = -10000

h = -10000/20

h = -500 m

negation of height shows the height against the gravitational force .

so,

maximum height at which ball will reach = 500 m

2.)

let the time taken by ball to come back to the thrower be t

by the motion law of gravitation

v = u + gt

putting the values,

0 = 10 + 10t

10t = -10

t = -10/10

t = -1

negation of time shows time taken to go upwards

now,

total tine taken = 2(1)

= 2 seconds

the time taken by the ball to come back to the thrower = 2 seconds

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Answer 2

2

3

2

.2

5

1

(2

3

2

+

5

1

)

(2 15

2×5+1×3

)

(2

15

10+3

)

2

15

13

tere pss brainly ka.old version h ky;)