Question

Question :- A balloon filled with Hydrogen at room temperature. It will burst if pressure exceeds 0.2 bar. If at 1 bar pressure the gas occupies 2.27 L volume, upto what volume can the balloon be expanded?​

Answer 1

Answer:-

Given:

Initial Pressure (P₁) = 1 bar

Initial Volume (V₂) = 2.27 L

Final Pressure (P₂) = 0.2 bar.

We know that,

Boyle's law of gases states that at constant temperature the pressure of a gas is inversely proportional to it's Volume.

→ P ∝ k/V (k is Constant)

→ PV = k

→ P₁V₁ = P₂V₂

Let the final Volume of hydrogen be V.

Hence,

→ (1) * (2.27) = (0.2) * (V)

→ 2.27/0.2 = V

→ 11.35 L = V

Hence, Hydrogen can occupy the volume of 11.35 L until it bursts.

Answer 2

$\huge\red{Solution☑}$

$v1 = 2.27 \: l;p1 = 1bar;p2 = 0.2bar$

$According\:to\:Boyle's\:law$

$p1 \: v1 = p2 \: v2$

❖the volume of the ballon should not

$exceed \: v2 = \frac{1*2.27}{0.2} = 11.35l$

$\red {Hope\:it\:help}⚡$