Question

Question:
A body moving with an initial
velocity of 6 m/s accelerates a
3 m/s2. Its velocity after 15
seconds is ....​

Answer 1

Answer:

By using formula

V=U+at

V=6+3×15

V=51 m/s

therefore

velocity after 15 s is 51m/s

Answer 2

Given :-

★ Initial velocity , u = 6m/s

★ Acceleration, a = 3 m/s²

★ Time, t =15 sec

To Find :-

★ Velocity after 15 sec

Solution :-

We know,

Equation of motion ___

$\boxed{\sf v = u +at}$

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

Substituting the values, we get ___

⟹ v = 6 + 15 × 3

⟹ v = 51 m/s

Hence,

Velocity after 15 sec is = 51 m/s

Know more :-

✰ What is velocity?

=> Velocity is the prime indicator of the position.

S.I unit : m/s

Common symbols: v

Dimension: L T−1