Question

QUESTION :
A body of mass M moving with velocity V makes a head on elastic collision with another body of mass 2M which is initially at rest. The ratio of kinetic energies of colliding body before and after collision will be?

Hoping answer from BRAINLY STARS.
@BeardoBoy ​​

Answer 1

Answer:

KE of colliding bodies before collision =1/2mv^2

after collision the mass = m+2m=3m

velocity become v^1=(m1-m2/m1+m2) v

=m/3m ×v

=v/3

KE after collision =1/2m(v/3) ^2

=1/9×1/2 mv^2

KE before/KE after=1/2mv^2/1/9×1/2mv^2

=9:1

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Answer 2

$\huge\bold\green{Required Answer}$

Checkout The Provided Attachment!

Points should be Remembered during solving :-

• K.E. = $\frac{1}{2} m {v}^{2}$

• V is the initial velocity and V` is the velocity after collision!

$\huge\bold\orange{ThankingYou!}$