Question: A can finish a piece of work in 48 days. He worked alone for 18 days anlone then B joined him and remaining work completed in 18 3/4 days then find how many days B alone can complete the work?
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Step-by-step explanation:
Work done by A in 48 days = 1 part
∴, " " " " " 1 day = 1/48 part
∴, " " " " " 18 days = 1/48 X 18 part = 3/8 part
∴, Work left = 1 - 3/8 part = 5/8 part
Work done by A and B together in 18 3/4(i.e. 75/4) days = 5/8 part
Work done by A and B together in 1 day= (5/8 ÷75/4)part = 1/30 part
A's one day work = 1/48 part
Thus, work done by B alone = (1/30 - 1/48)part = 15/48 part
Hence, no.of days needed by B to complete the work = (1÷15/48)days = 48/15 days = 3 3/15 days = 3 1/5 days.
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