Question

Question : A car is moving with velocity 90 km/h , suddenly car driver saw a speed breaker 100m away from the car . So, he applied brake to stop the car just before the speed breaker . So , what will be the value of applied brake and how much time it will take to stop the car ?
- Half Answer I'll do for you :)
S = 100 m
V = 0 m/s
U = 25m/s
V^2 = U^2 + 2AS
0 = 625+2×A×100m
-625M^2S^2÷100m = 2A
-6.25M/S^2 = 2A
-3.125M^2 = A (Value of Break applied)
Now please find the time...


FOR COPY-PASTERS - This question is not on internet so you have to do it by your own and if you answered wrong then I'll report you .Please watch it carefully and do ....​

Answer 1

$v = 0 m/s\: \\ u =25 m/s\\ s = 100m\\ a= ? \\ t = ? \\ {v}^{2} - {u}^{2} = 2 as \\ {0}^{2} - {25}^{2} = 2 \times 100 a\\ a= \frac{ - 625}{200} = - 3.125m/ {s}^{2} \\ s = ut + \frac{1}{2} a {t}^{2} \\ 100 = 25 t - \frac{3.125}{2} {t}^{2} \\ 3.125 {t}^{2} - 50 t+ 200 = 0 \\ t = 8s \\ \\ \\ hence, \: acceleration = - 3.125 m/ {s}^{2} \\ \: time \: taken = 8 \: sec \\ \\ please \: \: mark \: \: brainliest$