Question

QUESTION;
A car moving with constant acceleration covers the distance between two points 180 m apart in 6 sec.

Its speed as it passes the second point is 45 m/s. Its acceleration . [ ]

a) – 5 m/s² b) – 15 m/s²

c) 25 m/s² d) 5 m/s²

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Answer 1

Answer:

b) 15m/s²

Step-by-step explanation:

Since, v = u + a*t

180=6u+18a

30=u+3a..................(1)

45=u+at

45=u+a(6).................(2)

eq

n

(2)−eq

n

(1)

⇒15=3a⇒a=5

u=15m/s

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Answer 2

ANSWER

. 15m/sec.

$\large \star \large \underline \bold \red{Given}$

. ✏️The acceleration of Car between two different points is 6 sec.

. It's speed as it passes the second point.=45m/sec.

SOLUTION.

✏️.

$180 = u(6) + \frac{1}{2} a {(6)}^{2}$

$= 180 = 60 + 18a$

$3a = u + 3a.........(1)$

$45 = 4 + at$

$45 = 4 + a(6)...............(2)$

eq(2)-eq(1)

15 =3a=a=5

$\huge \ \boxed{u = 15mper \: sec}$