QUESTION;
A car moving with constant acceleration covers the distance between two points 180 m apart in 6 sec.
Its speed as it passes the second point is 45 m/s. Its acceleration . [ ]
a) – 5 m/s² b) – 15 m/s²
c) 25 m/s² d) 5 m/s²
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Answers
Answered by
9
✒ The initial velocity is 15 m/s and acceleration is 5 m/s².
✒ Speed of car = 45 m/s
✒ Distance = 180 m
✒ Time Taken = 6 s
✒ Acceleration of car = ?
We have been given the distance between two points (s) = 180 m
Time taken to cover the distance (t) = 6 s
Final velocity (v) = 45 m/s
So we need to find initial velocity and acceleration.
The first equation of motion is,
So,
From the second equation of motion:
Substitute (1) in (2),
Substitute the acceleration value in equation (1), we get,
Thus, the initial velocity is
15 m/s and acceleration is
Answered by
32
Answer:-
➣
• Given:-
• To Find:-
Acceleration of car =
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• Solution:-
Distance between two points (s) =
Time taken to cover the distance (t) =
Final velocity (v) =
Therefore, Finding the initial velocity and acceleration:-
• We know:-
The 1st equation of motion is:-
Hence,
Using the 2nd equation of motion:-
• We have:-
• Substituting (eqn.1) in (eqn.2):-
Putting, the value of acceleration [a] in equation (1):-
We have:-
Therefore,
•
•
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