QUESTION:
A circular park of radius 20m is situated in a colony.Three boys Ankur,Syed and David are sitting at equal distance on its boundary each having a toy telephone in his hands to talk each other.Find the length of the string of each place
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Answer:
Given
The positions of Ankur, Syed and David are represented as A, B and C respectively.
As they are sitting at equal distances, the triangle is equilateral
AD ⊥ BC is drawn.
AD is the median of ΔABC and it passes through the centre O.
O is the centroid of the ΔABC. OA is the radius of the triangle.
OA = 2/3 AD
Let the side of a triangle a metres then BD = a/2 m.
On applying Pythagoras theorem in ΔABD,
AB2 = BD2+AD2
⇒ AD2 = AB2 -BD2
⇒ AD2 = a2 -(a/2)2
⇒ AD2 = 3a2/4
⇒ AD = √3a/2
OA = 2/3 AD
20 m = 2/3 × √3a/2
a = 20√3 m
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Answer:
20√3
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