Question

Question: A constant horizontal
force of 250 N acts for a
distance of 36 m on a 500 kg
box. If friction is neglected and
the box starts from rest, what is
its velocity?​

Answer 1

Explanation:

Work

F = ma

250= 500 × a

a =0.5m/s^2

We know that,

v^2 = u^2 + 2as

v^2 = 0 + 2 × 0.5 × 36

【initially body was at rest , u=0】

【distance travelled = 36m, s= 36m】

v^2 = 36

v = +- 6

|v| = 6m/s

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