Question

Question: A convex mirror used in a bus has radius of curvature 3.5 metre and if the driver of the bus locate a car at 10 metre behind the bus find the position nature and size of the image of the car.

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Answer 1

Question: A convex mirror used in a bus has radius of curvature 3.5 metre and if the driver of the bus locate a car at 10 metre behind the bus find the position nature and size of the image of the car.

Solution:

Here,

$R = 3.5m$

$f = \frac{r}{2} = \frac{3.5}{2} = 1.75m$

$u = - 10.0m$

Step1: Determination of the position of the car.

Using,

$\frac{1}{u} + \frac{1}{v} = \frac{1}{f}$

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

$\frac{1}{v} = \frac{1}{1.75} - \frac{1}{( - 10)}$

$\frac{1}{v} = \frac{1}{1.75} + \frac{1}{10} \ = \frac{47}{70}$

$v = \frac{70}{47} = 1.49m$

Thus, the car appears to be at 1.49m from the convex mirror.

Answer 2

HELLO DEAR FRIEND

HERE IN CONCAVE MIRROR

RADIUS OF CURVATURE = 3.5 METER

FOCAL LENGTH =

$\large \bf \it{ \frac{ \large{radius \: of \:convature}}{ \large{2 }} }$

$\large \bf \it{ \frac{ \large{3.5}}{ \large{ 2}} }$

1.75m

AND GIVEN OBJECT DISTANCE(u) = -10m

$\large \bf \it{ \frac{ \large{1}}{ \large{v}} } = \large \bf \it{ \frac{ \large{1}}{ \large{1.75}} } - \large \bf \it{ \frac{ \large{1}}{ \large{(-10)}} }$

$\large \bf \it{ \frac{ \large{1}}{ \large{v}} } = \large \bf \it{ \frac{ \large{70}}{ \large{47}} }$

SO , v = 1.49 M

SO, IMAGE DISTANCE = 1.49 METER

HOPE IT HELPS YOU DEAR FRIEND THANKS