Question

Question: A convex mirror used in a bus has radius of curvature 3.5 metre and if the driver of the bus locate a car at 10 metre behind the bus find the position nature and size of the image of the car.
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Answer 1

Solution:

Here,

$R = 3.5m$

$f = \frac{r}{2} = \frac{3.5}{2} = 1.75m$

$u = - 10.0m$

Step1: Determination of the position of the car.

Using,

$\frac{1}{u} + \frac{1}{v} = \frac{1}{f}$

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

$\frac{1}{v} = \frac{1}{1.75} - \frac{1}{( - 10)}$

$\frac{1}{v} = \frac{1}{1.75} + \frac{1}{10} \ = \frac{47}{70}$

$v = \frac{70}{47} = 1.49m$

Thus, the car appears to be at 1.49m from the convex mirror.

Answer 2

Heya ____

Solution is _______

r = 3.5 metre

f = r/2 = 3.5/2 = 1.75m

u = -10.0 m

Position of car will be ____

1/u + 1/v = 1/f

1/v = 1/u - 1/f

1/v = 1.75 - ( 1/-10)

1/v = 1.75 + 1/10

1/v = 47 / 70

v = 70/47

= 1.49 m .....

So .. Position will be 1.49 m away... nature will be erect and convex..

Thank you