Question

★QUESTION★
A copper wire, 3 mm in diameter, is wound about a cylinder whose length is 12 cm, and diameter 10 cm, so as to cover the curved surface of the cylinder. Find the length and mass of the wire, assuming the density of copper to be 8.88 g per cm³
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$tell \: plz$
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Answer 1

Answer:

diameter of the wire =3 mm =3/10 cm

length of cylinder = 12 cm

diameter of cylinder =10 cm

therefore, one round of the wire covers 3/10 cm of the height of the cylinder,

thus wire will cover entire length of cylinder

therefore no. of rounds

3/10 cm covered in 1 round

1 cm = 1 × 10/3

12 cm = 12×10/3 rounds

=40 rounds

wire required for 1 round

isme kuch signs nahi hai so i can can't write further ....... sorry i can't be able to write whole ans.

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Answer 2

Answer:

ANSWER

From the figure we can observed that 1 round of wire will cover 3 mm height of cylinder.

Number of rounds =

Diameter of wire

Height of cylinder

=

0.3

12

=40 rounds.

Length of wire required in 1 round = Circumference of base of cylinder

=2πr=2π5=10π

Length of wire in 40 rounds =40×10π

=

7

400×22

=

7

8800

=1257.14 cm

=12.57 m

Radius of wire =

2

0.3

=0.15 cm.

Volume of wire = Area of cross-section of wire x Length of wire

=π(0.15)

2

×1257.14

=88.898 cm

3

Mass = Volume x Density

=88.898×8.88

=789.41 gm