Question

Question :-

A cork piece weighs 12.5 g. Initial volume of water in a measuring cylinder was
24 cm³. When a glass sinker was immersed
in water, the volume of water and sinker was found to be 56 cm³ When cork piece was tied to the sinker and both of
them were immersed in water, the volume reading in the measuring cylinder was 88 cm ³. Calculate the density of cork piece
in SI units.

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Answer 1

Answer:

Given:-

• Weight of cork piece = 12.5g
• Volume of water in cylinder = 24cm³
• Volume of water & Sinker = 56cn³
• Volume in measuring cylinder = 88cm³
• Volume of cork piece = 88 - 56 = 32cm³

Find:-

• Density of cork piece?

Solution:-

• ${ \boxed{ \sf{Density = \frac{Mass}{Volume} }}}$

$\to{ \sf{Density = \frac{12.5}{32} }} \\ \\ \to{ \sf{Density = \frac{125}{10} \times \frac{1}{32} }} \\ \\ \to{ \sf{Density = 0.390 \: g/ {cm}^{3} }}$

• SI unit of Density is kg/m³

$\to{ \sf{ \frac{0.390 \times 1 00 \times 1 00 \times 100 }{1 000 }kg / {m}^{3 } }} \\ \\ { \to{ \sf{ \frac{390000}{1000} kg / {m}^{3 }}}} \\ \\ \to{ \sf{390kg / {m}^{3 }}}$

${ \therefore { \underline{ \sf{ \blue{Density \: of \: cork \: piece = 390 kg/m³</p><p>}}}}}$