question-- (a) Find the circumcentre and the circumradius of the triangle whose vertices are (-2, -3), (-1,0)
and (7,6).
(b) Find the point equidistant from the points (1, 2), (3, 4) and (5, 6).
(c) Find the cicumcentre of the triangle whose vertices are (4,0), (0,4) and (-212, -2-2).
(d) Find the centre of the circle passing through the points (3,0), (2, v5) and (-212,-1).
(if don't know the answer better not answer)
Answers
Answer:
A] I DONT KNOW
B] The given three points are A(1,2) B(3,-4) and C(5,-6).
Let P (x, y) be the point equidistant from these three points.
So, PA = PB = PC
⇒ x^2 + 1– 2x + y^2 + 4 – 4y = x^2 + 9 -6x + y^2 + 16 + 8y = x 2 + 25– 10x + y^2 + 36 + 12y
⇒ – 2x– 4y + 5 = -6x + 8y +25= – 10x + 12y+61
– 2x– 4y + 5 = -6x + 8y +25
⇒ – 2x– 4y + 5 +6x – 8y -25=0
⇒ 4x– 12y -20=0
⇒ x– 3y – 5 =0….(i)
– 2x– 4y + 5 = – 10x + 12y+61
⇒- 2x– 4y + 5 +10x – 12y-61=0
⇒8x– 16y -56=0
⇒x– 2y -7=0….(ii)
Solving (i) and (ii)
x = 11, y = 2
Thus, the required point is (11, 2)
HOPE ITS HELPFUL AND PLEASE DONT REPORT MY ANSWER I KNOW MY AND DHRUV ANSWER YOU REPORT SO,PLEASE DONT REPORT THANKS....
Step-by-step explanation:
1 THING YOU REPORT MY ANSWER NOW IN DHRUV QUESTION YESTERDAY ALSO YOU REPORT NOW REALLY ANGRY :( YOU BROKE MY HEART.
Answer:
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