Question

QUESTION:
A force of 10N acting on a body of 3u with a horizontal direction display the body through a distance of 2m along the surface of a flow. Calculate the work done.

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Answer 1

Answer:

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Work done = force displacement (coso)

Work done = 10 2 cos60

cos60=1/2

$o,

work done = 10 2"1/2=10J

Explanation:

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Answer 2

Answer:

Work done = force displacement (coso)

Work done = 10 2 cos60

$o,

Work done = 10 2"1/2 = 10J

Explanation:

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