Question

QUESTION :-
A girl of mass 40 kg jumps with a horizontal velocity of 5 ms' onto a stationary cart with frictionless wheels. The mass of the cart is 3 kg. What is her velocity as the cart starts moving? Assume that there is no external unbalanced force working in the horizontal direction.

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Answer 1

Explanation:

Given-

• Mass of girl- 40 kg
• Initial velocity of girl- 5 m/s
• Mass of cart- 3kg
• Initial velocity of cart- 0 m/s

Let the final velocity of cart be V

Applying conservation of linear momentum:

➝ Pi = Pf

➝ (Mass×u) of girl + (Mass×u) of cart = ( M of girl+ M of cart)V

➝ 40×5+3×0 = (40+3)V

➝ V = $\frac{200}{43}$ m/s

Answer 2

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Answer:

200/43 ,43200 m/s

Explanation:

▪Mass of girl- 40 kgInitial

▪ velocity of girl- 5 m/s

▪Mass of cart- 3kg

▪Initial velocity of cart- 0 m/s

Let the final velocity of cart be V

Applying conservation of linear momentum:

j

➝ Pi = Pf

➝ (Mass×u) of girl + (Mass×u) of cart = ( M of girl+ M of cart)V

➝ 40×5+3×0 = (40+3)V

➝ V =

$\frac{200}{43}43200 m/s$

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