Question

Question→ A Hydrocarbon X have 81% of carbon . Volume of CO2 liberated at 298 K and 76 cm of Hg when 0.55 gm of x undergoes combustion?




Pagal ladki in the attachment xd
Apke karibi ne banayi hai I'd xdxd​

Answer 1

Answer:

100 g hydrocarbon corresponds to 81 g carbon.

0.55 g carbon corresponds to 0.4455 g carbon.

At given conditions, volume occupied by 1 mole of a gas is equal to V=

P

nRT

=

1

1×0.0821×298

=24.4658L

Thus, combustion of 12 g C will give 24.4658L CO

2

.

Hence, combustion of 0.4455 g carbon will give

12

24.4658

×0.4455=0.908LCO

2

.