Question

question: A pair of linear equations which has a unique solution x=2, y=-3 is
(A) x+y=-1
2x-3x=-5

(B) 2x + 5y =-11
4x + 10y = -22

(C) 2x -y=1
3x + 2y = 0

(D) x - 4y -14 = 0
5x-y-13=0
Choose the correct option and explain how..??? ​

Answer 1

Answer: (B) is the correct option

Step-by-step explanation: Since you already have been provided the solutions(x=2 and y=-3), you simply substitute these values in each of the equations and check whether the pair of equations are consistent with this solution.

In (B), we substitute x=2 and y=-3 in the first equation

2x + 5y = 2(2) + 5(-3) = 4 - 15 = -11 = R.H.S

Thus, this equation is consistent. Similarly, we verify if this is true for the second equation

4(2)+10(-3) = 8 - 30 = -22 = R.H.S

Thus, both equations are consistent with this solution.

Answer 2

Answer:

Step-by-step explanation:

Since they gave the value of x and y we substitute in the place of x and y

Like

2(2)+4(-3)=-11

4-15=-11

-11=-11

It is equal to rhs

4(2)+10(-3)=-22

8-30=-22

-22=-22

It is equal to rhs

For this pair of equation , it is the only solution