Question:
A person walked 10 m towards north Then he turned right and walks 20 m Then he turns right and walks 35 m. Then he tums right and walks
walks 25 m in which direction and how many meters is he from the starting position?
Answers
Answer:
= 25.50 m towards south-west
Step-by-step explanation:
As per question the data is given that,
A person start walking towards 10 m north direction,
then he turn right and walk 20 m ,
again he turn right and walk 35 m ahead,
now once again he turn to right and walk 25 m ahead.
So, as per figure that is depicted ,which make a right traingle .
whose perpendicular lenght = 25 m
and base = 5 m
And hypotenus is the shortest distance between initial and final position of the person.
So,
H² = P² + B²
H² = ( 25 )² + ( 5 )²
H² = 625 + 25
H² = 650
H = √650
H = 25.50 m
Threfore the distance between the initial and final position of the person is 25.50 m.
THANKS.
According to the figure, a right triangle is made after following the given data.
The perpendicular length of Right triangle formed = 25 m
base = 5 m
hypotenuse is the shortest distance between initial and final position of the person.
So,
H² = P² + B²
H² = ( 25 )² + ( 5 )²
H² = 625 + 25
H² = 650
H = √650
H = 25.50 m
∴ The person is 25.50 meters away from the starting position ( displacement) in the south-west direction.
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