Question

Question : A piece of metal weighs 50 N in air, 36 N in water and 41N in an unknown liquid. Find the densities of
(i) The metal and
(ii) The unknown liquid.

Answer 1

Answer:

3.57×10^3 kg/m^3 is the answer.....

Explanation:

In this case , firstly we would calculate the volume of the metal using it`s weight in air and water , after finding the weight we would find the density .

Weight of metal in air = 50N = mg implies mass of metal is 5kg

Now difference of weight of metal in air and water = upthrust acting on it = volume(metal)ρ (liquid)g=V(1000)(10)=14N

So volume of metal piece = 14×10^−4kg/m^3

So density of metal = mass of metal / volume of metal = 5/14×10^−4

= 3.57×10^3 kg/m^3

Hope it helps you