Question

Question:

A pole 6cm high casts a shadow 2√3 m long on the ground, then find the sun's elevation.

I'll mark the fastest answer as brainliest!!!

Answer 1

hope this answer will help you.

Answer 2

Answer :

The sun's elevation is 60°.

Step-by-step explanation :

In the figure, let the pole be AB.

The shadow of the pole is BC.

So,

$AB=6\:cm$

$BC=2\sqrt{3}$

Now, $tan\theta$ -

⇒ $\sf{\frac{AB}{BC}}$

⇒ $\sf{\frac{6}{2\sqrt{3}}}$

⇒ $\sf{\frac{3}{\sqrt{3}}}$

⇒ $\sf{\sqrt{3}}$

⇒ $tan\:60$° = $\sf{\sqrt{3}}$