Question:
A rectangular box has dimensions
x y ,
and
z
units, where
x y z
. If one dimension is only
increased by one unit, then the increase in volume is
(1) Greatest when
x
is increased
(2) Greatest when
y
is increased
(3) Greatest when
z
is increased
(4) The same regardless of which dimension is increased
Answers
✌️❣️_,_,_,_,_,_,_,_,_,_,_,_,_,_,_,_,_,_,_
Given P is equidistant from points A and B
PA=PB .....(1)
and Q is equidistant from points A and B
QA=QB .....(2)
In △PAQ and △PBQ
AP=BP from (1)
AQ=BQ from (2)
PQ=PQ (common)
So, △PAQ≅△PBQ (SSS congruence)
Hence ∠APQ=∠BPQ by CPCT
In △PAC and △PBC
AP=BP from (1)
∠APC=∠BPC from (3)
PC=PC (common)
△PAC≅△PBC (SAS congruence)
∴AC=BC by CPCT
and ∠ACP=∠BCP by CPCT ....(4)
Since, AB is a line segment,
∠ACP+∠BCP=180
∘
Thus, AC=BC and ∠ACP=∠BCP=90
∘
∴,PQ is perpendicular bisector of AB.
Hence proved.
Tusen Takk ✌️❣️
Answer:
your answer is
Step-by-step explanation:
Let the dimensions of rectangular box be 3,4,53,4,5 units
=> Volume = V=3\times4\times5=60V=3×4×5=60 cu units
Case 1 : New length = 44 units and breadth and height remains same
=> V'=4\times4\times5=80V ′ =4×4×5=80 cu units
Case 2 : New breadth = 55 units and length and height remains same
=> V'=3\times5\times5=75V ′ =3×5×5=75 cu units
Case 3 : New height = 66 units length and breadth remains same
=> V'=3\times4\times6=72V ′ =3×4×6=72 cu unitsClearly, increase in volume is greatest when xx is increased
.=> Ans - (A)
I hope its help you