Question

Question :

A resistor is of 4 ohms and the length of the conducting wire is doubled and the area of transverse cut is half than find the change in the resistance.

___Please Answer Soon....It's Urgent..____

:D

#No - Spams!

Answer 1

$\large{\boxed{\tt{Answer:-}}}$

Given:-

Resistance (R) = 4 ohm.

Length of wire (l) = l

Area of Cross section = A

$\large{\boxed{\tt{Explanation:-}}}$

★We know that:-

R = ρ I / A

★Apply the values to the equation:-

4 = ρ l/A

$R_f = \rho 2l / A 2$

$R_f =4 \rho l / A$

$R_f = 4R$

$R_f = 16 ohm$

Hence, the charge in the resistance is 16 ohm.

Answer 2

let initial resistor length be l and area is a

so

R = row* l/a

row*l/a = 4-------(1

New resistor

length double = 2l

area is half = a/2

so new resistor = 4row *l/a

putting the value of -------(1

R = 4*4=16ohm