Math, asked by shantoshshrivastav19, 6 months ago

Question:
A ribbon is (10x-8)metres long. A length of
(7x-5) metres is cut from it how much
ribbon is left?​

Answers

Answered by hanockgamer611
4

Answer:

Given,

length of wire =(7x−3)m

and wire cut for use has length =(3x−4)m

Left wire =(7x−3)−(3x−4)=(4x+1)m

(b) Left wire =(4x+1)m

Perimeter of equilateral triangle = Length of wire left

⇒ 3×side=4x+1

⇒ side=3(4x+1)=31(4x+1)m

Answered by loveyourself1508
14

Answer:

3x - 13

Step-by-step explanation:

Given,

Length of the ribbon- (10x-8)m

Length of the ribbon cut - (7x-5)m

Now,

Length of the ribbon left= (10x-8) - (7x-5)

= 10x - 8 - 7x - 5

= 10x - 7x - 8 - 5

= 3x -13

length of the left ribbon= 3x - 13

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