Question

QUESTION:-
A shopkeeper bought two items at ₹ 450 each. He sold one at loss of 10%. At what price should he sell the other so as to gain 20% on the whole transaction?
TOPIC : PROFIT OR LOSS
SUBJECT: MATHS ​​

Answer 1

Answer:

Loss of 10%

$450 \times \frac{10}{100} \\ 45$

so he sold it at 450 - 45 = 405

So he should sold it by

450 + 450 × 20 / 100

$900 \times \frac{20}{10 0} \\ 180 \: \: rs$

So he should sold it at

900 + 180 = 1080 rs

1080 rs - 405

= 675 rs

hope this helps you out

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Answer 2

Given:

A shopkeeper bought two items at 450 each

He sold one item at 10% loss

To find:

At what price should he sell the other as to gain 20% on the whole transaction?

Solution:

Let "x" represents the selling price of the other item.

The total cost price of the two items = Rs. 450 × 2 = Rs. 900

We will use the following formula:

$\begin{gathered}\boxed{\bold{S.P. = \frac{100 - L\%}{100}\times C.P. }}\\\\\boxed{\bold{S.P. = \frac{100 + G\%}{100}\times C.P. }}\end{gathered}$

Using the above formula, we get,

∴ The S.P. of the first item is,

=$\dfrac{100 - 10}{100}$

= $\dfrac{90}{100}\times 450$

= 0.9×450

= ₹405

and

∴ The total S.P. of the two items is,

=$\dfrac{100 + 20}{100} \times 900$

= $\dfrac{120}{100}\times 900$

= 1.2×900

= ₹1080

Now,

The S.P. of the other item should be,

= (Total S.P. of the two items) - (S.P. of the first item)

= (Rs. 1080) - (Rs. 405)

= Rs. 675