Math, asked by Anonymous, 3 months ago

Question-
A slab whose dielectric constant is K, is attached to a string of linear mass density u, while its one end is fixed to a rigid support. Its cross section has sqaure plates of side b and seperation between them is d. Find the fundamental frequency of the vibration of the string.​

Attachments:

xxxmysterxxx: ok
xxxmysterxxx: C=
d

0





C

=
d−t+
k
t



0





Put t=
4
3d

;

C

=
3+k
4k

.
d

0





C

=
3+k
4k

.C
xxxmysterxxx: answer
xxxmysterxxx: tq
xxxmysterxxx: I t will like in question in comments it's coming like this
xxxmysterxxx: sorry
Anonymous: oh.. but thanks very much
xxxmysterxxx: its ok
Anonymous: hmm
xxxmysterxxx: hi

Answers

Answered by Evilhalt
644

 \huge \underline \mathrm{answer}

The equation of a travelling wave propagating along the positivey-direction is given by the displacement equation:  ...(i) Linear mass density, Frequency of the tuning fork, Amplitude of the wave,   ...(ii) Mass of the pan, m   Tension in the string, The velocity of the transverse wave v, is given by the relation:     Angular Frequency,                                                                              ...(iii) Wavelength, Propagation constant,                                                ...(iv) Substituting the values from equations (ii), (iii), and (iv) in equation (i), we get the displacement equation: .

Answered by Anonymous
6

Let us write the given data and solve the question

Density = U

Cross section of plates = b

Separation = d

Fundamental frequency (n) = ?

SOLUTION:

Let us use that formula here

n = 1/2L √T/μ

As we already know the value of T from the given data

Let us try to derive the value of T

T = -dU/dx = 1/2(k-1)E₀ bV²/ d equation 1

Let us apply the value of T in frequency formula (n)

Then,

n = 1/2L √(k-1)E₀bV² /2dμ

This is final equation

Attachments:
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