Question-
A slab whose dielectric constant is K, is attached to a string of linear mass density u, while its one end is fixed to a rigid support. Its cross section has sqaure plates of side b and seperation between them is d. Find the fundamental frequency of the vibration of the string.
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Let us write the given data and solve the question
Density = U
Cross section of plates = b
Separation = d
Fundamental frequency (n) = ?
SOLUTION:
Let us use that formula here
n = 1/2L √T/μ
As we already know the value of T from the given data
Let us try to derive the value of T
T = -dU/dx = 1/2(k-1)E₀ bV²/ d equation 1
Let us apply the value of T in frequency formula (n)
Then,
n = 1/2L √(k-1)E₀bV² /2dμ
This is final equation or Fundamental Frequency which we require
If it is confusing please refer the given attachment
Sorry for the inconvenience
Hope it helps
Thanks for asking
Stay blessed and safe
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Anonymous:
Great nice
Answered by
2
Answer:
Let us write the given data and solve the question
Density = U
Cross section of plates = b
Separation = d
Fundamental frequency (n) = ?
SOLUTION:
Let us use that formula here
n = 1/2L √T/μ
As we already know the value of T from the given data
Let us try to derive the value of T
T = -dU/dx = 1/2(k-1)E₀ bV²/ d equation 1
Let us apply the value of T in frequency formula (n)
Then,
n = 1/2L √(k-1)E₀bV² /2dμ
This is final equation or Fundamental Frequency which we require
If it is confusing please refer the given attachment
Sorry for the inconvenience
Hope it helps
Thanks for asking
Stay blessed and safe
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