Physics, asked by Anonymous, 11 months ago

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QUESTION:

A stone tied to the end of a string 80cm long is whirled in a horizontal circle with a constant speed . If the stone makes 14 revolutions in 25s , what is the magnitude and direction of acceleration of the stone ?

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Answers

Answered by N3KKI
40

Length of the string, l = 80 cm = 0.8 m

Number of revolutions = 14

Time taken = 25 s

Frequency, v = Number of revolutions / Time taken = 14 / 25 Hz

Angular frequency, ω = 2πν

= 2 × (22/7) × (14/25) = 88 / 25 rad s-1

Centripetal acceleration, ac = ω2r

= (88/25)2 × 0.8

= 9.91 ms-2

The direction of centripetal acceleration is always directed along the string, toward the centre, at all points

Answered by Anonymous
3

Answer:

Answer is here:-

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