Question

Question:

A teacher is 18 years elder to her student. 3 years ago one-tenth of the teacher's age was equal to one-fourth of the student's age. Find their present ages.


Solve the upper question with explanation and write it in detail

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Answer 1

Answer:

Step-by-step explanation:

Answer 2

Question:-

A teacher is 18 years elder to her student. 3 years ago one-tenth of the teacher's age was equal to one-fourth of the student's age. Find their present ages.

Given:-

• A teacher is 18 years elder to her student.

• 3 years ago one-tenth of the teacher's age was equal to one-fourth of the student's age.

To Find:-

• Their present ages.

Solution:-

Let, student age is x.

So, teacher age = x + 3.

According to question:

$\sf \large \frac{1}{10} (x + 18 - 3) = \frac{1}{4} (x - 3)$

$\sf \large⇒ \frac{x + 15}{10} = \frac{x - 3}{4}$

$\sf \large⇒ \frac{x + 15}{10} = \frac{x - 3}{4}$

$\sf \large⇒10(x - 3) = 4(x + 15)$

$\sf \large⇒10x - 30 = 4x + 60$

$\sf \large⇒10x - 4x = 60 + 30$

$\sf \large⇒6x = 90$

$\sf \large⇒x = {{ \cancel{ \frac{90}{6} }}} = 15$

• Teacher's age is 15 + 18 = 32.

• Student age is 15.

Answer:-

${ \boxed{ \sf \large \green{ \therefore \: Teacher's age = 32. \: and}}} \\ { \boxed{ \sf \large \red{ \therefore Student \: age = 15.}}}$

Hope you have satisfied. ⚘