Question

Question- A train is travelling at a speed of 60 km/ h. Brakes are applied so as to produce a uniform acceleration of −0.5 m /s2 . Find how far the train will go before it is brought to rest.

Answer 1

Explanation:

Initial velocity, u = 60 km/h

= 60×1000/3600 m/s¹

= 60000/3600 m/s¹

= 600/36 m/s¹

= 16.67 m/s

Final velocity, v = 0 m/s

Acceleration, a = - 0.5 m/s²

Distance travelled =?

Using, = v² = v² - u²/2a

S = v² - u²/ 2a

= 0² - 16.67²/2(-05)

= 227.889 m/s².

Therefore, Train will go 277.889 m before it brought to rest.

Answer 2

Answer:

Here, initial speed, u=90km/h−1=90×1000m60×60s=25m/s

acceleration, a=−0.5m/s2, final velocity, v=0, distance travelled, s=?

From v2−u2=2as, s=v2−u22a=0−(25)22×(−0.5)=625m

Explanation:

Here, initial speed, u=90km/h−1=90×1000m60×60s=25m/s

acceleration, a=−0.5m/s2, final velocity, v=0, distance travelled, s=?

From v2−u2=2as, s=v2−u22a=0−(25)22×(−0.5)=

625m