Physics, asked by Anonymous, 1 month ago

Question:-

A train starts its journey from one station to another at a distance of 190 km and reach after 2 hrs. It takes 3 Hours to come back to the initial station. What will be the average velocity and average speed of the train?

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Answers

Answered by Anonymous
56

Given :

  • ➬ A train starts its journey from one station to another at a distance of 190 km and reaches after 2 hrs. It takes 3 hours to come back to its initial station.

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To Find :

  • ➬ Average Speed = ?
  • ➬ Average Velocity = ?

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Solution :

Formula Used :

\large{\orange{\bigstar}} \: \: \: {\underline{\boxed{\red{\sf{ Average \: Speed = \dfrac{Total \: distance }{ Total \: Time}}}}}}

Calculating Average Speed :

Here :

Distance will be double as the train first travelled 190 km and it again travelled 190 km to return to its initial position. Hence,

  • ➳ Distance covered = 190 + 190 = 380 km

Time taken he took 2 hrs to go to its destination and returned in 3 hrs. Hence,

  • ➳ Total Time = 3 + 2 = 5 hrs

Calculation starts :

{:\longmapsto{\qquad{\sf{ Average \: Speed = \dfrac{Total \: Distance}{Total \: Time}}}}}

{:\longmapsto{\qquad{\sf{ Average \: Speed = \dfrac{380}{5}}}}}

{:\longmapsto{\qquad{\sf{ Average \: Speed = \cancel\dfrac{380}{5}}}}}

\qquad{\sf{ Average \: Speed \: = {\color{darkblue}{\sf{ 76 \: km/h}}}}}

\qquad{━━━━━━━━━━━━━━━━━━━━}

Calculating Average Velocity :

Here :

As we know if an object travels and distance and returns its initial position using same path in that condition the Displacement of the object is always 0. If the displacement is the 0 than the velocity is also 0.Hence,

Calculation starts :

\qquad{\sf{ Average \: Velocity \: = {\color{orange}{\sf{ 0 \: km/h}}}}}

\qquad{━━━━━━━━━━━━━━━━━━━━}

Therefore :

❝ Average Speed of the train is \blue{\underline{\red{\sf{ 76 \: km/h}}}} .❞

❝ Average velocity of the train is \blue{\underline{\red{\sf{ 0 \: km/h}}}} .❞

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Know more :

3 equations of motion :

\begin{gathered}\red{\large \qquad \boxed{\boxed{\begin{array}{cc} \ ➳ \: \: \bf v = u + at \\ \\ \ ➳ \: \: \bf s = ut + \dfrac{1}{2}a {t}^{2} \\ \\ \ ➳ \: \: \bf{v}^{2} - {u}^{2} = 2as\end{array}}}}\end{gathered}

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