Question

Question:- AABC is an isosceles triangle. If AB = AC and AD are in the middle of BC, find Corner BAD. ​

Answer 1

Answer:

∠ADB = 90° [because AD is the middle of BC]

∠ABD + ∠BAD + ADB = 180°

55 + ∠BAD + 90 = 180°

145 + ∠BAD = 180°

∠BAD = 180 - 145

∠BAD = 35

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