Question
△ABC ∼ △ PQR, A (△ ABC) = 289 cm² A (△ PQR) = 144 cm². Find (BC/QR)
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bro sorry I didn't know
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By thm of area of similar triangle. A1^2/A2^2=s1^2/s2^2. hence BC =17 and QR=12. Thanks 0.
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