Question

Question :-
An amount of Rs. 100000 is invested in two types of shares. the first yields an interest of 9% p.a. and the second, 11% p.a. If the total interest at the end of one year is 9(3/4)%, then the amount invested in each share was:

Answer 1

Answer:

Let the sum invested at 9% be Rs. x and that invested at 11% be Rs. (100000 - x).

Then,

=(x×9×1100)+[(100000−x)×11×1100]=(100000×394×1100)⇔9x+1100000−11x100=390004=9750⇔2x=(1100000−975000)=125000⇔x=62500∴Sum invested at 9%=Rs. 62500Sum invested at 11%  = Rs.(100000−62500)=Rs. 37500

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Amount - 100000

2 shares -9% & 11% p.a ,year end total int. 39/4

9% 11℅

39/4

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then , 36%. 44%

39%

5%. 3%

now invested amount a1 - 100000× (5/100)/8 = 12500 ×5= 62500

a2 - 100000× (3/100)/8 = 12500 ×3=37500