Question

Question :

An object of 1 kg is attached to the string at the height of 100 m from the ground. What is the velocity of the object when it impacts on the ground, if it is released from string at 100 m?
Take acceleration due to gravity g=9.8 m/s^2 . ​

Answer 1

u= 0

s = 100m

a = 9.8 m/s^2

v = ?

v ^2 = u^2 + 2as

v ^2 = 0 + 2 × 9.8 × 100

v^2 = 196

v =√196 = 44.27 m/s

Answer 2

Answer:

44.27188 m/s

Explanation:

If it is a free fall then the velocity of the body at the ground = √2gh

= √ 2 * 9.8 * 100

= √1960

= 44.27188 m/s

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