Math, asked by FuturePoet, 1 year ago

Question as below :-

If after 5 years 'A' will be thrice as old as 'B' . At present 'B' is 5 times older than ' C ' Whose age before 3 years was 3 years . The present age of 'A' is

Answers

Answered by Anonymous
3
Given Information
(A +5) = 3(B+5) - i
5C = B - ii
C- 3 = 3 - iii

Now from iii
Present age of C = 6

then from ii
B = 5 C
=> present age of B = 30

Now from i
A+5 = 3(B+5)
=> A = 3B + 15 - 5
=> A = 120 +10
=> A = 130 years


Hope it helps (if it is correct )!!
Answered by Anonymous
13

Let A be of A years.

Let B be of B years

Let C be of C years

Now:

after 5 years A will be thrice as old as B

==> A + 5 will be thrice as B + 5

==> A + 5 = 3 ( B + 5 )

==> A + 5 = 3 B + 15

==> A = 3 B + 15 - 5

==> A = 3 B + 10 ....................................................(1)

Now:

B is 5 times older than C

==> B = 5 C ................................................(2)

Now

C ' s age before 3 years was 3 years:

===> C - 3 = 3

==> C = 6.................................(3)

Putting the value of C in 2 we get:-

B = 5 C

==> B = 5 * 6

==> B = 30

Putting this value of B in (1) we get:-

A = 3 B + 10

==> A = 3 * 30 + 10

==> A = 90 + 10

==> A = 100

The present age  of A is 100 years

Hope this helps you !

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Anonymous: yes
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