Question

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Answer 1

Answer:

angle ECD =105°

as BCD is a 180°line

= 180°-105°

=75° hence angle ECB =75°

angle 2

EAF =45°

as an opposite angle

BAC = EAF= 45°

now we have two angle

so,

angle A + angle B + angle C =180°

45° + angle B + 75° = 180°

120° + angle B =180°

angle B = 180° -120°

angle B = 60°

angle A =45°

angle B =60°

angle C =75°

how this helps