Question

Question attached below

Answer 1

Step-by-step explanation:

x-2 = 0

x= 2

(x-2) is the zeros of given polynomial

so ,

2x^3 + ax^2 -11x + b

2×2^3 + a× 2^2 -11×2 + b

16 + 4a - 22 + b

4a+ b - 6

b = 6 -4a i )

x-3 = 0

x= 3

2x^3 + ax^2 -11x +b -42

2× 3^3 + a ×3^ 2 -11×3 + ( 6-4a) -42

54+ 9a - 33 +6-4a -42

5a +60 - 75

5a - 15

5a= 15

a = 15/5

a = 3 Ans

from eq. i)

b = 6- 4a

b = 6 - 4× 3

b = 6-12

b = -6 ANS