Math, asked by supritnaik100, 11 months ago

Question based on algebra

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Answered by amitnrw
2

Answer:

x + y + z max value  = 36 if c ≥ 3

Step-by-step explanation:

x + cy ≤ 36

2x + 3z  ≤ 72

Adding both

3x + cy + 3z ≤ 108

if c ≥3

then c = 3 + a   where a≥0

3x + (3+a)y  + 3z ≤ 108

=> 3x + 3y + 3z  ≤ 108 - 3ay

dividing by 3 both sides

x + y + z ≤  36 - ay

x + y + z is mas when a = 0

x + y + z max value  = 36

Answered by mkrishnan
0

i hope i do best

but still I have a doubt

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mkrishnan: mark me brainliest
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