Question based on algebra
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Answer:
x + y + z max value = 36 if c ≥ 3
Step-by-step explanation:
x + cy ≤ 36
2x + 3z ≤ 72
Adding both
3x + cy + 3z ≤ 108
if c ≥3
then c = 3 + a where a≥0
3x + (3+a)y + 3z ≤ 108
=> 3x + 3y + 3z ≤ 108 - 3ay
dividing by 3 both sides
x + y + z ≤ 36 - ay
x + y + z is mas when a = 0
x + y + z max value = 36
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i hope i do best
but still I have a doubt
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mkrishnan:
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