Question

question based upon finding zeros of given polynomial and verifying the relation between the their zeros and coffecient of polynomial : x²- 7x- 8​

Answer 1

the other two zeroes are 8, -1

pls refer my attchment...

Answer 2

Answer:

${x}^{2} - 7x - 8 = 0 \\ {x}^{2} - 8x + x - 8 = 0 \\ x(x - 8) + 1(x - 8) = 0 \\ (x - 8)(x + 1) = 0 \\ x - 8 = 0 \\ x = 0 + 8 \\ x = 8 \\ x + 1 = 0 \\ x = 0 - 1 \\ x = - 1 \\ the \: zeroes \: are \: 8 \: and - 1$

here is the answer

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