Question: calculate the amount of iron formed when 0.9 mol carbon monoxide reacts work excess iron (ll) oxide.
Fe2O3+3CO=2Fe+3CO2
GUYS MY QUESTION IS HOW DID THEY GOT 2/3.
Attachments:
Answers
Answered by
1
Answer:
I not udeastood the question
Answered by
0
Answer:
its simple - they took the mol of Fe [which is 2] and the mole of CO [which is 3] and they divided it .
Explanation:
i know this question was 2years ago but imma answer it for the people in da future :]
Similar questions