Question

QUESTIONˊ★᭄ ࿐ :- Calculate the amount of water (g) produced by the combustion of 16 g of Methane.

 
:.Only Correct ✔︎ Answer ࿐​

Answer 1

Answer:

The balanced equation for the combustion of methane is :

CH4(g)+2O(g)→CO2(g)+2H2O(g)

(i) 16 g of CH4 corresponds to one mole

(ii) From the above equation .1 mol of

CH4(g) gives 2 mol of H2O (g)

2 mol of water (H2O)=2×(2+16)

=2×18=36g

1 mol H2O=18gH2O⇒18gH2O1molH2O

Explanation:

hope it is helpful for you and please mark me brainiest please follow and give lots of thanks also

Answer 2

Answer:

The balanced equation for the combustion of methane is :

CH4(g)+2O(g)→CO2(g)+2H2O(g)

(i) 16 g of CH4 corresponds to one mole

(ii) From the above equation .1 mol of

CH4(g) gives 2 mol of H2O (g)

2 mol of water (H2O)=2×(2+16)

=2×18=36g

1 mol H2O=18gH2O⇒18gH2O1molH2O

=2×18gH2O=36gH2O

Hope this helps you dear please fo.llow me and give thanks to my answers

@itzbrandedkamina ❤❤