Question

Question:-
Charan started walking from a point and walked 16m towards the east. He then took a right turn and walked
7m. He again took a right turn and walked 7m. Finally, he took a left turn and walked for 5m. What is the
distance (in metres) between his initial and final position?
Choices:-
15
16
17
​

Answer 1

Given:

The distances travelled by Charan

To find:

Distance (in metres) between his initial and final position

Solution:

According to the given conditions-

1. Charan started walking from the initial point( marks as S) and covered 16m towards the east.

S--------------->( East)

      16m

2. A right turn and walked

7m.

S----------------->( East)

        16m             |    7m

                        (South)

3. Again a right turn and walked 7m.

S----------------->( East)

        16m             |    7m

       <--------------(South)

               7m

4. One last left turn and walked for 5m.

S----------------->( East)

        16m             |    7m

           <---------(South)

    5m  |      7m

     (South)

So as observed, Charan is in the south-east direction with respect to his initial position.

To find the distance between initial and final point, we make an imaginary triangle, SOF( given in the attached figure).

Solving it using Pythagoras theorem-

SO= 9m

OF= 12m

So, SF ( hypotenuse) = √ ( 81+144) = √225 or 15m

Distance (in metres) between his initial and final position is 15m.