Question

✫QUESTION✫


Compare the power used in the 2 Ohm resistor in each of the following circuits: (i) a 6 V battery in series with 1 Ohm and 2 Ohm resistors, and (ii) a 4 V battery in parallel with 12 Ohm and 2 Ohm resistors.

$EXPLANATION$​

Answer 1

Answer:

Hello mate,

1 st situation Potential difference, V = 6 V

1Ohm and 2 Ohm resistors are connected in series. Therefore, equivalent resistance of the circuit, R = 1 + 2 = 3 Ohm

According to Ohm’s law,

V = IR

Where,

I is the current through the circuit

I= 6/3 = 2 A

This current will flow through each component of the circuit because there is no division of current in series circuits. Hence, current flowing through the 2Ohm resistor is 2 A. Power is given by the expression,

P= (I)2R = (2)2 x 2 = 8 W

2 nd situation(ii) Potential difference, V = 4 V

12 Ohm and 2 Ohm resistors are connected in parallel. The voltage across each component of a parallel circuit remains the same. Hence, the voltage across 2 Ohm resistor will be 4 V.

Power consumed by 2 Ohm resistor is given by

P= V2/R = 42/2 = 8 W

Therefore, the power used by 2 Ohm resistor is 8 W.

Answer 2

Answer:

✫ ANSWER ✫

Potential difference (V) = 6 V

Here 1 Ω and 2 Ω resistors are connected in series.

∴ equivalent resistance of the circuit (R) = 1 + 2 = 3 Ω

According to Ohm’s law

V = IR

Or I=V/R=6/3=2A

the current through the circuit (I)=2A

Now the power used in the 2 Ω resistor

we know that Power = I2R

= 2×2×2=8W